This is how you work out the answer to the Cross + Roads = Danger riddle.
CROSS
+ ROADS
----------------
DANGER
Well you can see that the DANGER has one more letter than CROSS and ROADS, and the extra letter is D. That means that C + R equals something more than 10. Which also means D is 1. So now we have this equation...
CROSS
+ ROA1S
---------------
1 ANGER
And this key...
C=?
R=?
O=?
S=?
A=?
D=1
E=?
N=?
G=?
Now look at the equation below (same as one just above)
In the equation, O + A = G. We have 2, 5, 7 and 8 vacant. Let's play around with these letters. Let's see if we can find an equation in there. Yes! There is an equation there. 5 + 2 = 7! So G must equal 7. We know that 9 + 6 = 15, but it's missing the 5! So, A must equal 5. In turn, this leads to O having to be 2 (do the maths, O + 5 = 7). And last of all, O is 2, so 6 + 2 (6 + O) = N But 6 + 2 = 8, so now N is 8. We now have the following equation...
96233
62513
------------
158746
And the following key...
N=8
CROSS
+ ROADS
----------------
DANGER
Well you can see that the DANGER has one more letter than CROSS and ROADS, and the extra letter is D. That means that C + R equals something more than 10. Which also means D is 1. So now we have this equation...
CROSS
+ ROA1S
---------------
1 ANGER
And this key...
C=?
R=?
O=?
S=?
A=?
D=1
E=?
N=?
G=?
Now look at the equation below (same as one just above)
CROSS
+ ROA1S
---------------
1 ANGER
Oh look, S + S = R. That means that R must be even. We have a choice of 4, 6 and 8, because if R was 2, S would have to be 1, and D is already 1. Let's try 6 for the value of R, because we need high numbers if we want C + R to equal something more than 10. Oh look, if R is 6 and S is R divided by 2, then S must be 3!
Now we have this key...
N=?
G=?
And this equation...
Now we have this key...
C=?
R=6
O=?
S=3
A=?
D=1
E= ?
N=?
G=?
And this equation...
C6O33
+ 6OA13
---------------
1 ANGE6
Well it's pretty obvious that 3 + 1 = 4, so now we have E down as 4. And since we now only have 4 spots in the key left, we choose the highest number for C, which is 9. Again, we need high numbers to make C + R equal something more than 10.
Now we have this key...
C=9
R=6
O=?
S=3
A=?
D=1
E= 4
G=?
And this equation...
96O33
+ 6OA13
---------------
1 ANG46
In the equation, O + A = G. We have 2, 5, 7 and 8 vacant. Let's play around with these letters. Let's see if we can find an equation in there. Yes! There is an equation there. 5 + 2 = 7! So G must equal 7. We know that 9 + 6 = 15, but it's missing the 5! So, A must equal 5. In turn, this leads to O having to be 2 (do the maths, O + 5 = 7). And last of all, O is 2, so 6 + 2 (6 + O) = N But 6 + 2 = 8, so now N is 8. We now have the following equation...
96233
62513
------------
158746
And the following key...
C=9
R=6
O=2
S=3
A=5
D=1
E= 4
G=7
Congratulations, you have now finished the CROSS + ROADS = DANGER puzzle.
This post has been made originally by Jose.
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